Integrand size = 20, antiderivative size = 112 \[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=-\frac {(A b-a B) (d+e x)^{1+m}}{b (b d-a e) (a+b x)}+\frac {(a B e (1+m)-b (B d+A e m)) (d+e x)^{1+m} \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {b (d+e x)}{b d-a e}\right )}{b (b d-a e)^2 (1+m)} \]
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Time = 0.04 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {79, 70} \[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\frac {(d+e x)^{m+1} (a B e (m+1)-b (A e m+B d)) \operatorname {Hypergeometric2F1}\left (1,m+1,m+2,\frac {b (d+e x)}{b d-a e}\right )}{b (m+1) (b d-a e)^2}-\frac {(A b-a B) (d+e x)^{m+1}}{b (a+b x) (b d-a e)} \]
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Rule 70
Rule 79
Rubi steps \begin{align*} \text {integral}& = -\frac {(A b-a B) (d+e x)^{1+m}}{b (b d-a e) (a+b x)}-\frac {(a B e (1+m)-b (B d+A e m)) \int \frac {(d+e x)^m}{a+b x} \, dx}{b (b d-a e)} \\ & = -\frac {(A b-a B) (d+e x)^{1+m}}{b (b d-a e) (a+b x)}+\frac {(a B e (1+m)-b (B d+A e m)) (d+e x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac {b (d+e x)}{b d-a e}\right )}{b (b d-a e)^2 (1+m)} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.88 \[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\frac {(d+e x)^{1+m} \left (-\frac {(A b-a B) (b d-a e)}{a+b x}+\frac {(a B e (1+m)-b (B d+A e m)) \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {b (d+e x)}{b d-a e}\right )}{1+m}\right )}{b (b d-a e)^2} \]
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\[\int \frac {\left (B x +A \right ) \left (e x +d \right )^{m}}{\left (b x +a \right )^{2}}d x\]
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\[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\int { \frac {{\left (B x + A\right )} {\left (e x + d\right )}^{m}}{{\left (b x + a\right )}^{2}} \,d x } \]
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\[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\int \frac {\left (A + B x\right ) \left (d + e x\right )^{m}}{\left (a + b x\right )^{2}}\, dx \]
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\[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\int { \frac {{\left (B x + A\right )} {\left (e x + d\right )}^{m}}{{\left (b x + a\right )}^{2}} \,d x } \]
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\[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\int { \frac {{\left (B x + A\right )} {\left (e x + d\right )}^{m}}{{\left (b x + a\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {(A+B x) (d+e x)^m}{(a+b x)^2} \, dx=\int \frac {\left (A+B\,x\right )\,{\left (d+e\,x\right )}^m}{{\left (a+b\,x\right )}^2} \,d x \]
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